What is dV in KSP?

Use the atmospheric and vacuum thrust values for atmospheric and vacuum Δv, respectively.

How do you maximize delta V in KSP?

There are four basic techniques to increase the delta-V of a spacecraft:

  1. Use more efficient engines (ones with higher Isp).
  2. Increase fuel mass by adding more tanks, though this has diminishing returns.
  3. Reduce dry mass (anything that is not fuel, reducing upper stage mass is most important).

How much dV do you need for Duna?

With proper aerobraking, a round trip from Kerbin to Duna’s orbit and back requires roughly 1700 m/s of delta-v, less than a round trip to any other planet. Duna is often the easiest planet to achieve encounters because of a low orbital inclination.

How much thrust do I need KSP?

Because the gravitational acceleration on Kerbin’s surface is roughly 10 m/s², 10 kN per ton or 100 kg per unit of thrust result in a thrust-to-weight ratio of about 1. This represents the minimum for launch; a TWR in the range 1.5 to 2.5 is better.

How much DV does it take to orbit kerbin?

Reaching a stable orbit around Kerbin is one of the first milestones the player achieves in the game. Achieving such an orbit with a fuel-optimal ascent requires a delta-V of roughly 4500 m/s, the second largest of all celestial bodies with a solid surface after Eve.

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Is Minmus easier than Mun?

It’s not easier to get to, it’s about 100 m/s beyond and the difficulty of the encounter is compounded by both its relative inclination and it’s smaller sphere of influence. The easy part is when it comes to take off/landing. Minmus has a gravitational acceleration of .

How much dV do I need to return to Minmus?

Adding a 10% buffer totals 1,617 m/s of delta-V. For Minmus, the numbers are 180 m/s for descent and ascent, and 160 for the return.

Is delta-v the same as acceleration?

The ratio delta-v/delta-t is called the acceleration. If the acceleration is not constant and the time interval is finite then this ratio is the average acceleration. Acceleration is the slope of the velocity-time graph.

Is DV the same as delta-v?

1. When we use “delta” rather than “d”, we mean that, say “delta v”/”delta t” is the average change in “v” over the non-zero time interval “delta t”. 2. Now, dv/dt is what we call the instantaneous rate of change in “v”, that is the limit of “delta v”/”delta t” as we let the time interval “delta t” shrink to zero.

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